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  • 22-05-2018
  • Mathematics
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8z=4(2z+1) show step by step

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keilynlovescats
keilynlovescats keilynlovescats
  • 22-05-2018
8z=4(2z+1)
First you would distribute the constant into the numbers in the parentheses. so
8z=8z+4
then you would combine like terms which in this case would result in a zero.
8z-8z=0 So the z would be zero or no solution.
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