Respuesta :

2x^2-4x-30 would be your answer

(2x−10)(x+3)
=(2x+−10)(x+3)
=(2x)(x)+(2x)(3)+(−10)(x)+(−10)(3)
=2x2+6x−10x−30
=2x2−4x−30
gmany
Use distributive property:
[tex](a+b)(c+d)+ac+ad+bc+bd[/tex]

[tex](2x-10)(x+3)=2x\cdot x+2x\cdot3-10\cdot x-10\cdot3\\\\=2x^2+6x-10x-30=2x^2-4x-30[/tex]