Answer:
a + b = 1
Step-by-step explanation:
We have the roots of ax²+bx+c = 0 as [tex]\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex].
Sum of roots [tex]=\frac{-b+\sqrt{b^2-4ac}}{2a}+\frac{-b-\sqrt{b^2-4ac}}{2a}=-\frac{b}{a}[/tex]
Here equation is x²-x-90 = 0
a = 1, b = -1 and c = -90
Sum of roots = a + b [tex]=-\frac{b}{a}=-\frac{-1}{1}=1[/tex]
a + b = 1
