taylorlawrence27651 taylorlawrence27651

21-07-2018
Chemistry

contestada

The ionization constant for water (kw) is 9.311 × 10−14 at 60 °c. calculate [h3o+], [oh−], ph, and poh for pure water at 60 °c.

Respuesta :

30-07-2018

As,

Kw = [H+] [OH-]

For water, [H+] = [OH-]

Therefore we can write

Kw = [H+]²

9.311 × 10-14 = [H+]²

[H+] = 3.04 × 10-7 = [OH-]

Ph = - log [H+]

= - log ( 3.04 × 10-7)

= 6.52

Thus, Ph = PoH = 6.52

Answer Link

Otras preguntas

Describe the consequences of the French and Indian war on two groups that participated in the war

40 POINTS and will give BRAINLIEST if correct!! ASAP

A horse can run 165 feets in 3 minutes. How far does it travel per minute?

James has terminal cancer. If his disease progresses to the point that he can't make decisions for himself, James wants to make sure his healthcare workers are

The following questions contain hands-on exercises that require a personal EMS Training Environment, also called an "EMS Team". Please go to Studio and create a

Describe the end behavior of the function f(x) = 4x³ 16x² 8 As xgoes to ∞, f(x) goes to As xgoes to -∞, f(x) goes to

Everything is filtered through the listener’s _________________ ______ ___________________, which is the sum of a person’s knowledge, experience, goals, values,

What is the prime factorization of 84

12 minutes for 6 songs = minutes per song

Question: Plastic that enters the ocean eventually breaks down into microscopic particles called. Answer Input: Spelling counts but capitalization doesn't.