fnaticshockwave
fnaticshockwave fnaticshockwave
  • 22-07-2018
  • Mathematics
contestada

Explain why you would arrive at a complex solution when dealing with the zeros of a quadratic function.

Respuesta :

ralphwx1 ralphwx1
  • 22-07-2018
Any quadratic equation, ax^2 + bx + c = 0 can be rearranged into a(x - h)^2 = k, a > 0
A is positive and the square of a real number is nonnegative. Thus, if x is real, the left side is nonnegative. But sometimes, k is negative, so that a real solution for x wouldn’t work, and a complex solution becomes necessary.
Answer Link

Otras preguntas

Identify whether the solubility of Ag_2CrO_4 will increase or decrease by adding the following agents. a. Na2CrO4 b. HCl c. NH3
an experiment involving the scientific method begins with a/an:
does liner mean ship?????
Please help ASAP 17x - 4(4x - 3)
i really need this answer
Select all of the following that have the same value as 30,452. A. (3 x 1,000) + (4 x 100) + (5 x 10) + (2 x 1) B. (3 x 104) + (4 x 10') + (5 x 10²) + (2 x 10'
Need help ASAP pls thx
What about India and China country war did China really want war, What about you??​
Which set of ordered pairs does not represent a function? {(7, -5), (-5, -2), (8, –9), (-9,0)} {(-3,0), (0, -5), (6,-2), (1, -2)} {(6, -6), (-9,2), (6, -1), (
Find the equivalent equation that results from, halving both sides first and then subtracting 1 from both sides. Show each step. You do not have to solve the eq