fatboicroi
fatboicroi fatboicroi
  • 25-09-2018
  • Mathematics
contestada

plz help me asap and plz show work

plz help me asap and plz show work class=

Respuesta :

FelisFelis FelisFelis
  • 05-10-2018

Looking at the image it can be seen that equation says:

[tex]ax^2=bx[/tex]

Now we have to figure out which of the options are correct:

From, [tex]ax^2=bx[/tex]

Solving for 'x' we get:

[tex]x=\frac{b}{a}[/tex]

Now, [tex]ax^2=bx[/tex]

[tex]ax^2-bx=0[/tex]

[tex]x(ax-b)=0[/tex]

Solving for 'x' we get:

[tex]x=0[/tex], [tex]ax-b=0[/tex], which gives [tex]x=\frac{b}{a}[/tex].

So, we can see that among all the options given, [tex]x=0[/tex] and  [tex]x=\frac{b}{a}[/tex] is correct.

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