Answer: [tex]\frac{3}{2}[/tex][tex](\frac{1}{2})^{n-1}[/tex]
Step-by-step explanation:
[tex]\frac{3}{2}, \frac{3}{4}, \frac{3}{8}, \frac{3}{16}, \frac{3}{32}, ...[/tex]
common ratio (r) = [tex]\frac{1}{2}[/tex]
first term (a₁) = [tex]\frac{3}{2}[/tex]
[tex]a_{n}[/tex] = a₁ (r)ⁿ⁻¹
= [tex]\frac{3}{2}[/tex][tex](\frac{1}{2})^{n-1}[/tex]
