Hi there!
Here we go:
2x + 1 ≤ [tex]\frac{3(x+1)}{2}[/tex]
You need to multiply each side of the equation by 2
4x + 2 ≤ 3(x + 1)
You need to distribute the 3 to the entire parentheses
4x + 2 ≤ 3x + 3
You need to subtract 3x from each side of the equation
x + 2 ≤ 3
You need to subtract 2 from each side of the equation
x ≤ 1
There you go! I really hope this helped, if there's anything just let me know! :)
