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Do Statement and Reason


Given: ∆DEK, DE = KE, EF− ∠ bisector of ∠E

m∠DEF = 44°, DK = 16


Find: m∠DEK, KF

Respuesta :

wegnerkolmp2741o

Answer:

see below

Step-by-step explanation:

1. m∠DEF = m∠_FEK___ = 44° = Def. of ∠ bisector  

2. m∠DEK = m∠_DEF___+m∠FEK___= _angle addition postulate________________

3. m∠DEK = _44___ + _44___ = 88° = Substitution, Algebra  

4. DE = _KE____ = Given  

5. EF = _FE____ = Reflexive property

6. △DEF ≅ △_KEF____ = _SAS postulate________________

7. DF = FK_____ = ___CPCTC  (corresponding parts of congruent triangles are congurent)______________

8. KF = 1/2DK =8 _____ = Algebra, 7

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