Answer:
8[tex]\sqrt{2}[/tex]
Step-by-step explanation:
Rationalise the denominator by multiplying both the numerator and denominator by the radical on the denominator, that is
[tex]\frac{32}{\sqrt{8} }[/tex]
= [tex]\frac{32\sqrt{8} }{8 }[/tex] → ([tex]\sqrt{8}[/tex])² = 8
= [tex]\frac{32\sqrt{4(2)} }{8}[/tex]
= 4× 2[tex]\sqrt{2}[/tex]
= 8[tex]\sqrt{2}[/tex]
