Answer:
[tex]\large\boxed{B.\ \dfrac{7}{8}}[/tex]
Step-by-step explanation:
[tex]\text{Put the values}\ x=\dfrac{15}{8}\ \text{and}\ y=-3\ \text{to the expression}\ \dfrac{3}{8}y^2-\dfrac{4}{3}x:\\\\\dfrac{3}{8}(-3)^2-\dfrac{4}{3\!\!\!\!\diagup_1}}\cdot\dfrac{15\!\!\!\!\!\diagup^5}{8}=\dfrac{(3)(9)}{8}-\dfrac{(4)(5)}{8}=\dfrac{27}{8}-\dfrac{20}{8}=\dfrac{27-20}{8}=\dfrac{7}{8}[/tex]
