jayvenmariscalr jayvenmariscalr

21-09-2019
Physics

contestada

A car slows down from 45 m/s to rest in a distance of 91 m.

What was its acceleration, assumed constant?

Respuesta :

ch3ng27 ch3ng27

21-09-2019

Answer:

a = -11.1 m/s²

Explanation:

Initial velocity, u = 45 m/s

Final velocity, v = 0 m/s

Distance travelled, s = 91m

Using

v² = u² + 2as

0 = 45² + 2(91)a

a = -11.1 m/s²

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