BrooklynR4610 BrooklynR4610
  • 21-10-2019
  • Mathematics
contestada

Consider the polynomial P(x)=x³+kx²+x+6.Find the value of k so that x+1 is a factor of P.

Respuesta :

aristeus aristeus
  • 22-10-2019

Answer:

The value of k will be -4      

Step-by-step explanation:

We have given polynomial [tex]P(X)=x^3+kx^2+x+6[/tex]

It is given that x+1 is factor of the polynomial

And we have to find the value of k

As x+1 is the factor of polynomial  so x+1 = 0 that is x = -1 will be the root of polynomial

So if we put x = -1 in the polynomial then the p(-1) will be zero

So [tex]0=(-1)^3+k(-1)^2-1+6[/tex]

[tex]k=-4[/tex]

So the value of k will be -4

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