Answer:
72 and 73
Step-by-step explanation:
let the first locker number be "y"
Hence, the next locker number [consecutive] would be "y+1"
Since the SUM is 145, we can add up the two and write and equation. Then simply solve algebraically. Shown below:
[tex]y+y+1=145\\2y+1=145\\2y=145-1\\2y=144\\y=\frac{144}{2}\\y=72[/tex]
So, the 2 locker numbers are 72 and 73
