Answer:
[tex]2 m/s^2[/tex]
Explanation:
The acceleration of an object is given by:
[tex]a=\frac{v-u}{\Delta t}[/tex]
where
v is the final velocity
u is the initial velocity
[tex]\Delta t[/tex] is the time interval
For the body in the problem, we have:
[tex]u=10 m/s[/tex] at t = 1 s
[tex]v=48 m/s[/tex] at t = 20 s
So the time interval is
[tex]\Delta t = 20 -1 = 19 s[/tex]
And so, the acceleration is
[tex]a=\frac{48-10}{19}=2 m/s^2[/tex]
