Answer:
[tex]f'(x)=3x^2-2x+2[/tex]
Step-by-step explanation:
Assuming that the function is
[tex]f(x)=(x-1)(x^2+2)[/tex]
First, we need to remove the parenthesis. Once this is done, we get
[tex]f(x)=x^3-x^2+2x-2[/tex]
Now that the parenthesis are gone, we can differentiate each term. To do this, we can use the power rule, which states
[tex]f(x)=x^n\\f'(x)=nx^{n-1}\\[/tex]
This gives us
[tex]f'(x)=3x^2-2x+2[/tex]
