Answer:
The line segment EF=11x-3
Step-by-step explanation:
Given that D is the midpoint of EF , ED=4x+6 and DF=7x-9
To find the EF :
Let EF is a line segment and D its midpoint(given)
EF=ED+DF
=(4x+6)+(7x-9)
=4x+6+7x-9 ( adding the like terms )
=11x-3
Therefore EF=11x-3
Therefore the line segment EF=11x-3
