Answer:
The work energy added to the gas is
W = -72.48472 kJ
Explanation:
For constant pressure process
Work is given W = p×[tex](V_{f} - V_i)[/tex]
However dH = m×[tex]c_{p} (T_2-T_1)[/tex] = 1875 J
For mass m, dQ = 2625 J
That is m×1875 = 2625 or m = 2625/1875 = 1.4 kg
Therefore work doneper unit mass of gas is -W = p×(v₂ - v₁)
but pv = RT therefore work done per unit mass = -R×(T₂ - T₁) = -R×ΔT and
ΔT = 180.4K
Work done = -1.4×0.287×180.4 = -72.48472 kJ
