Step-by-step explanation:
Suppose AB is the 3- foot high access ramp that ends at point C 20 feet along the ground and
theta is the angle of depression from the start of 3 foot high ramp at point A
Now, in ∆ ABC
m<ACB= theta ( alternate interior angle)
Therefore,
[tex] \tan(theta) = \frac{AB}{BC} [/tex]
[tex] \tan(theta) = \frac{3}{20} [/tex]
(theta) = tan⁻¹(3/20)
= 8.5°
