Answer:
The amount of energy added to rise the temperature Q = 17413.76 KJ
Explanation:
Mass of water = 52 kg
Initial temperature [tex]T_{1}[/tex] = 68 °F = 20° c
Final temperature [tex]T_{2}[/tex] = 212 °F = 100° c
Specific heat of water [tex]C = 4.186 \frac{KJ}{kg c}[/tex]
Now heat transfer Q = m × C × ( [tex]T_{2}[/tex] - [tex]T_{1}[/tex] )
⇒ Q = 52 × 4.186 × ( 100 - 20 )
⇒ Q = 17413.76 KJ
This is the amount of energy added to rise the temperature.
