The first step in solving this is to substitute x with 3 and y with 2, so that
[tex]\frac{1}{3} x^{2} +5.2y[/tex]
becomes
[tex] \frac{1}{3} (3)^{2} +5.2(2)[/tex]
Then simply solve using the order of operations.
First exponents (there are no parentheses)
[tex] \frac{1}{3} 9 +5.2(2)[/tex]
Then multiply and divide
[tex]3+10.4[/tex]
And finally add and subtract
[tex]13.4[/tex]
Therefore the value of 1/3 x^2 + 5.2y when x=3 and y=2 is 13.4
