voltage in primary coil V_p = 120 V
current through primary coil I_ p = 1 A
current through secondary coil I_s = 10 A
a) Voltage across secondary coil
V_s = ( I_p / I_s ) V _ p
= ( 1 / 10 ) 120
= 12 V
number of turns in the secondary coil N _s =800
b) number of turns in the primary coil
N _ p = ( I _s / I_p ) N_s
= ( 1 / 10 ) 800
= 80 turns
c) power out put by the transformer
P = I _p V_p
240 W = I _p ( 120 V )
primary current in the transformer at maximum power in theoutput
I_p = 2 A
