Answer:94.0 g H2O
Explanation:
2H2 + O2 --> 2H2O
The
question asked me how many grams of water will form if 10.54 g H2 react with 95.10 g O2.
The correct answer was 94.0g of H2O I got from
10.54g H2 * 1 mol H2/2.02 g/mol H2 * 2 mol H2O/2 mol H2 = 5.22 mol H2O
95.10g O2* 1 mol O2/32 g/mol O2 * 2 mol H2O/1 mol O2 = 5.94 mol H2O
The limiting reactant is 5.22 mol, which 5.22 mol H2O * 18.01 g/mol H2O = 94.0g H2O.
