Answer:
[tex] x = 18°\\
\angle A = 73°[/tex]
Step-by-step explanation:
By interior angle property on one side of the transversal.
[tex] \angle A+ \angle B = 180°\\
6x - 35° + 3x + 53° = 180°\\
9x + 18° = 180°\\
9x = 180° - 18°\\
9x = 162°\\
x = \frac{162°}{9}\\
\huge \red {\boxed {x = 18°}} \\
\therefore \angle A = 6x - 35°\\
\therefore \angle A = 6\times 18°- 35°\\
\therefore \angle A = 108°- 35°\\
\huge \purple {\boxed{\therefore \angle A = 73°}} \\[/tex]
