kittybiancacardenas kittybiancacardenas

22-06-2020
Mathematics

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Find the sum of the first 31 terms of the following series, to the nearest integer. 5 , 14 , 23 , . . .

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devishri1977 devishri1977

23-06-2020

Answer:

Step-by-step explanation:

a1 = 5

common difference = 2nd term - 1st term= 14 -5 = 9

n = 31

[tex]S_{n}=\frac{n}{2}[2a+(n-1)d]\\\\S_{31}=\frac{31}{2}[2*5+30*9]\\\\=\frac{31}{2}[10+270]\\\\=\frac{31}{2}*280\\\\=31*140\\\\=4340[/tex]

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