Answer:
8×10⁻¹⁷ N
Explanation:
from the question, Electric force is given as
F = QV/r.............. Equation 1
Where F = Electric Force, Q = Charge, V = Electric potential, r = distance.
Given: Q = 8×10⁻¹⁹ C, V = 5 kV = 5000 V, r = 2 cm = 0.02 m.
Substitute into equation 1
F = 8×10⁻¹⁹(5000)(0.02)
F = 8×10⁻¹⁷ N
Hence the electric force on the dust particle is 8×10⁻¹⁷ N
