Answer:
2
Step-by-step explanation:
Given that:
11th term of a geometric sequence is 32 times larger than the 6th term
The nth term of a geometric sequence is given by:
An = A*r^(n-1)
Where An = the nth term ; r = common ratio and n = term number ; A = first term
The 11th term:
A6 = A*r^(6 - 1) = Ar^5
A11 = 32A6 = 32Ar^5
A11 = Ar^(11 - 1) = Ar^10
Hence,
Ar^10 = 32Ar^5
r^(10 - 5) = 32
r^5 = 2^5
Hence, r = 2
