2460673
2460673 2460673
  • 22-10-2020
  • Mathematics
contestada

Solve and show your work or explain.
[tex]x-\sqrt{2x-5}=5[/tex]

Respuesta :

DemonicBrain
DemonicBrain DemonicBrain
  • 22-10-2020

Answer:

[tex]x= 6+ \sqrt {6}[/tex]

Step-by-step explanation:

[tex]-\sqrt {2x-5}+x=5\\-\sqrt {2x-5}=-x+5\\\\\frac {-\sqrt {2x-5}}{-1} = \frac {-x+5}{-1}\\\\\sqrt {2x-5}=x-5\\2x-5=(x-5)^2\\2x-5=x^2-10x+25\\2x-5-(x^2-10x+25)=x^2-10x+25-(x^2-10x+25)\\-x^2+12x-30=0\\\\x=\frac {-12(+/-)\sqrt {12^2-4(-1)(-30)}}{2(-1)}\\\\x=6+\sqrt {6}[/tex]

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