Answer:
Explanation:
Let the volume required be v litre .
moles of KOH in v litre of .558 M of KOH = v x .558 moles
1 mole of KOH reacts with 1 mole of HCl
v x .558 moles of KOH reacts with v x .558 mole of HCl
v x .558 = .016
v = .016 / .558
= .02867 litre
= 28.67 mL .
