keayuna1317ozhqk3 keayuna1317ozhqk3
  • 21-12-2020
  • Mathematics
contestada

Helppppppp meeeee ASAP

Helppppppp meeeee ASAP class=

Respuesta :

jacobEwing
jacobEwing jacobEwing
  • 21-12-2020

Answer:

A and D

Step-by-step explanation:

[tex]x = \frac{-b (+/-) \sqrt{b^2 - 4ac} }{2a}\\\\x = \frac{3 (+/-) \sqrt{9 - 4 * 1 * 5} }{2 * 1}\\\\x = \frac{3 (+/-) \sqrt{-11} }{2}[/tex]

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