Answer:
(4π/3+2πn; 5π/3+2πn)
Step-by-step explanation:
1. to calculate the zeros:
sinx=-sqrt(3)/2; ⇔
[tex]x=(-1)^{n+1}*(\frac{\pi }{3})+\pi *n[/tex], where n∈Z.
2. using the zeros found and the attached picture:
x∈(4π/3+2πn; 5π/3+2πn).
