Answer:
2%
Step-by-step explanation:
so the point [tex](\sqrt{3},\sqrt{7})[/tex] is in the circumference so the distance from (0,0) to this point will be the radius of the bullseye
[tex]x=\sqrt{(\sqrt{3}-0)^2+(\sqrt{7}-0)^2}\\\\x=\sqrt{3+7}\\\\x=\sqrt{10}[/tex]
so that's the radius
so the area will be
[tex]A=\pi x^2\\\\A=\pi (\sqrt{10})^2\\\\A=10\pi[/tex]
so the percentage is
[tex]P=\frac{A}{1600}\\\\=\frac{10\pi}{1600}\\\\=\frac{\pi}{160}\\\\P\approx 0.02[/tex]
so it's 2%
