dimakamal456 dimakamal456
  • 22-01-2021
  • Physics
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A force of 62 N acts on a 35 kg object for 10.0s. What is the objects change in momentum?

Respuesta :

cjrodriguez89
cjrodriguez89 cjrodriguez89
  • 22-01-2021

Answer:

Δp = 620 N.s

Explanation:

  • Newton's second law, was originally conceived  as follows:

       [tex]F = \frac{\Delta p}{\Delta t} (1)[/tex]

  • In this way, a net force applied on an object, is equal to the rate of change of the momentum of the object regarding time.

       for m= constant, it reduces to F= m*a.

  • Replacing in (1) F= 62 N, and Δt = 10.0 s, we can solve for Δp (object's change in momentum) , as follows:

       [tex]\Delta p = F* \Delta t = 62 N* 10.0 s = 620 N*s (2)[/tex]

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