Answer:
Genotypic- 1:1
Phenotypic- 1:1
Explanation:
For this problem, I will use the letter A to represent the alleles. The first parent's genotype would be Aa, and the second parent would be aa. Then, using a punnet square to cross the two parents the outcome is Aa, Aa, aa, aa. This means there is a 50% of a mixed individual and a 50% of a purebred recessive. Both phenotypes also have a 50% chance of being expressed. Since the percentages are equal both ratios are 1:1.
