Answer:
[tex]F_{net}[/tex] is 26.25 N
Explanation:
Given that: [tex]F_{x}[/tex] = 20 N, [tex]F_{y}[/tex] = 17 N.
This implies that the two forces are acting at right angle to each other. Thus applying the Pythagoras theorem, we have;
[tex]F_{net}[/tex] = [tex]\sqrt{F_{x} ^{2} + F_{y} ^{2} }[/tex]
= [tex]\sqrt{(20)^{2} + (17)^{2} }[/tex]
= [tex]\sqrt{400 + 289}[/tex]
[tex]F_{net}[/tex] = [tex]\sqrt{689}[/tex]
= 26.2488
[tex]F_{net}[/tex] = 26.25 N
The net force is 26.25 N.
