archerv213 archerv213
  • 23-04-2021
  • Mathematics
contestada

evaluate the intergral2x(xsquared+3)exponent 4​

Respuesta :

goodingoodbye1 goodingoodbye1
  • 23-04-2021

Answer:

(x^2+3)^5/5 + C

Step-by-step explanation:

Here substitute u = x^2 + 3 , du/dx = 2x ---> dx= 1/2x du

Then: integral (u^4) du

Apply power rule: u^5/5

Then replace the substitution u=x^2+3 in u

= (x^2+3)^5/5 + C

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