Answer:
The reaction takes place is
2 (C2H6) + 7 (O2) → 4(CO2) + 6(H2O)
According to the equation,
60g ethane requires 7x32= 224g oxygen
here ethane is in excess.oxygen will be consumed completely.
hence
2.9 g O2 will consume 60×2.9/224=0.776g of C2H6
now,
2 moles of C2H6 produces 4 moles of CO2!
60g ethane produces 4x44 g CO2
hence amount of CO2 produced =4×44×0.776/60=2.27g
