Question:-
Algebraically, find the roots of x² - 4x - 5 = 0
Solution:-
x² - 4x - 5 = 0 (Given equation)
Here a = 1, b = -4 and c = -5
[tex] \therefore [/tex] b² - 4ac = (-4)² - (-4) × 1 × -5 = 16 - 20 = -4 < 0
There are no real roots for the given equation. [Answer]
