Answer:
[tex] \displaystyle {9}^{2x - 1} = 2[/tex]
Step-by-step explanation:
we are given a logarithmic equation
[tex] \displaystyle \log_{9}(2) = 2x - 1[/tex]
we want to rewrite it as exponential equation
remember that,
[tex] \displaystyle\log_{a}(b) = c \iff {a}^{c} = b[/tex]
here our a is 9,b is 2 and c is 2x-1
altogether
our exponential equation is
[tex] \displaystyle {9}^{2x - 1} = 2[/tex]
and we're done!
