Answer:
(2x + 5)(3x - 7), (x + 4)(x - 2)
Step-by-step explanation:
a = 6, b = 1, c = -35
? × ? = ac = 6 × -35 = - (2 × 3 × 7 × 5)
? + ? = b = 1
3 × 5 -(negative sign from above) 2 × 7 = 15 - 14 = 1 = b
[tex]\frac{1}{6}(6x + 15)(6x + (-14))[/tex]
= [tex]\frac{1}{6}(3)(2x + 5)(2)(3x - 7)[/tex]
= [tex](2x + 5)(3x - 7)[/tex]
a = 1, b = 2, c = -8
? × ? = ac = 1 × -8 = -(2 × 2 × 2) = 4 × -2
? + ? = b = 2
4 + (-2) = 2 = b
[tex]\frac{1}{1}(1x + 4)(1x + (-2))[/tex]
= [tex](x + 4)(x - 2)[/tex]
