Answer:
[tex]y=\frac{8x}{1}-7\\[/tex]
Step-by-step explanation:
(1,1) and (2,9)
[tex]\frac{9-1}{2-1}[/tex] =[tex]\frac{8}{1\\}[/tex]
(2,9) and (x,y)
[tex]\frac{y-9}{x-2} =\frac{8}{1} \\\\1(y-9)=8(x-2)\\\\\frac{1y}{1}-\frac{9}{1}=\frac{8x}{1}-\frac{16}{1}\\\\y=\frac{8x}{1}-16+9\\y=\frac{8x}{1}-7[/tex]
