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  • 25-08-2021
  • Mathematics
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Determine the value of k for which the graph of y=kx^3 pass through the point (-2,1)

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xKelvin
xKelvin xKelvin
  • 25-08-2021

Answer:

[tex]\displaystyle k = -\frac{1}{8}[/tex]

Step-by-step explanation:

We are given the equation:

[tex]\displaystyle y = kx^3[/tex]

And we want to determine the value of k such that the graph passes through the point (-2, 1).

Hence, when x = -2, y = 1. Substitute:

[tex]\displaystyle (1) = k(-2)^3[/tex]

Simplify:

[tex]\displaystyle 1 = -8k[/tex]

Hence:

[tex]\displaystyle k = -\frac{1}{8}[/tex]

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