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Question : 14
let's solve for f :
- [tex] \dfrac{1}{f} = \dfrac{1}{a} + \dfrac{1}{b} [/tex]
- [tex] \dfrac{1}{f} = \dfrac{b + a}{ab} [/tex]
Taking reciprocal of both sides :
- [tex]f = \dfrac{ab}{a + b} [/tex]
