Answer:
Explanation:
Let x be the leaf spring compression distance
F = kx
5.20 x 10⁵ = (5.45 x 10⁵)x + (3.80 x 10⁵)(x - 0.500)
5.20 x 10⁵ = (5.45 x 10⁵)x + (3.80 x 10⁵)(x) - 1.90 x 10⁵
7.10 x 10⁵ = (9.25 x 10⁵)x
x = 0.76756...
x = 0.768 m
W = ½(5.45 x 10⁵)0.768² + ½(3.80 x 10⁵)(0.768 - 0.500)²
W = 174,148.648648...
W = 174 KJ
