shularja shularja
  • 22-02-2022
  • Mathematics
contestada

please helpppp btw not sure if the letter clicked is right or not it just won’t let me un select lol

please helpppp btw not sure if the letter clicked is right or not it just wont let me un select lol class=

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boatengalbert291
boatengalbert291 boatengalbert291
  • 22-02-2022
Is wrong please
Answer is (a) 2

Proof
f(x)=(x^2) + 1.


g(x) = x + 2

f[g(-1)]

First considering g(-1)

g(-1)=(-1) + 2 = 1

f[g(-1)] = f(1)

=(1^2) + 1

=1+1=2

Hence f[g(-1)]=2
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