The maximum height the ball will reach is 7.6 ft.
Maximum height of the projectile
The maximum height attained by the projectile is calculated as follows;
v² = u² - 2gh
where;
- v is the final velocity at maximum height = 0
- u is the initial velocity
- h is the height
- g is acceleration due to gravity
0 = u² - 2gh
2gh = u²
[tex]h = \frac{u^2}{2g} \\\\h = \frac{10^2}{2(32.2)} \\\\h = 1.6 \ ft[/tex]
Thus, the maximum height the ball will reach = 1.6 ft + 6ft = 7.6 ft.
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