Answer:
[tex]32\ in^2[/tex]
Step-by-step explanation:
The area of a trapezoid is:
[tex]A=\frac{b_1+b_2}{2}*h[/tex]
[tex]b_1b_2[/tex] represent the two bases of the trapezoid.
We can substitute the given lengths into the equation:
[tex]A=\frac{6+10}{2}*4\\A=\frac{16}{2}*4\\A=8*4\\A=32\ in^2[/tex]
