Answer:
3.088 m/s²
Explanation:
Let's see which variables we are given in this problem.
- Δx = -105 m
- v₀ = -27.7 m/s
- v = -10.9 m/s
- a = ?
The kinematics equation that includes these four variables is:
Substitute the known variables into the equation and solve for a.
- (-10.9)² = (-27.7)² + 2a(-105)
- 118.81 = 767.29 - 210a
- -648.48 = -210a
- a = 3.088 m/s²
The car's acceleration while slowing down from 27.7 m/s to 10.9 m/s in 105 m is 3.088 m/s².
