Answer:
Areas and volumes of cylinders etc
Step-by-step explanation:
Given:
h = 10.7 in
V = 619 in^3
Volume (V) = π[tex]r^{2}[/tex]h
619 = 22/7×[tex]r^{2}[/tex]×10.7
∴[tex]r^{2}[/tex] = 619x7/ 22x10.7
r = 4,3 in approx.
Please check calculation for me but thats how one proceeds
