26-01-2017
Physics

contestada

a 10-N force is exerted on a box, moving it 20 m in the same direction. What is the magnitude of work done on the box?

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TheHero TheHero

26-01-2017

F = 10 N

d = 20 m

θ = 0°

W = F (dot product) D = F * D * cos(angle between them)

W = FDcosθ

W = 10 * 20 * cos0 = 200 J

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